A small tool to view real-world ActivityPub objects as JSON! Enter a URL
or username from Mastodon or a similar service below, and we'll send a
request with
the right
Accept
header
to the server to view the underlying object.
{
"@context": [
"https://www.w3.org/ns/activitystreams",
{
"ostatus": "http://ostatus.org#",
"atomUri": "ostatus:atomUri",
"inReplyToAtomUri": "ostatus:inReplyToAtomUri",
"conversation": "ostatus:conversation",
"sensitive": "as:sensitive",
"toot": "http://joinmastodon.org/ns#",
"votersCount": "toot:votersCount",
"blurhash": "toot:blurhash",
"focalPoint": {
"@container": "@list",
"@id": "toot:focalPoint"
}
}
],
"id": "https://mathstodon.xyz/users/davidradcliffe/outbox?min_id=0&page=true",
"type": "OrderedCollectionPage",
"next": "https://mathstodon.xyz/users/davidradcliffe/outbox?max_id=57978&page=true",
"prev": "https://mathstodon.xyz/users/davidradcliffe/outbox?min_id=109311370356524623&page=true",
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109311370356524623/activity",
"type": "Announce",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-11-09T01:59:02Z",
"to": [
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],
"cc": [
"https://mathstodon.xyz/users/PedanticOwl",
"https://mathstodon.xyz/users/davidradcliffe/followers"
],
"object": "https://mathstodon.xyz/users/PedanticOwl/statuses/109311337267102763"
},
{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109310825988472698/activity",
"type": "Announce",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-11-08T23:40:36Z",
"to": [
"https://www.w3.org/ns/activitystreams#Public"
],
"cc": [
"https://mastodon.social/users/Alisca",
"https://mathstodon.xyz/users/davidradcliffe/followers"
],
"object": "https://mastodon.social/users/Alisca/statuses/100729027558904090"
},
{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109310570673157880/activity",
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"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-11-08T22:35:40Z",
"to": [
"https://www.w3.org/ns/activitystreams#Public"
],
"cc": [
"https://mathstodon.xyz/users/johncarlosbaez",
"https://mathstodon.xyz/users/davidradcliffe/followers"
],
"object": "https://mathstodon.xyz/users/johncarlosbaez/statuses/109262546588286591"
},
{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109309898480596154/activity",
"type": "Create",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-11-08T19:44:43Z",
"to": [
"https://www.w3.org/ns/activitystreams#Public"
],
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"object": {
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109309898480596154",
"type": "Note",
"summary": null,
"inReplyTo": null,
"published": "2022-11-08T19:44:43Z",
"url": "https://mathstodon.xyz/@davidradcliffe/109309898480596154",
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"atomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/109309898480596154",
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"conversation": "tag:mathstodon.xyz,2022-11-08:objectId=28683306:objectType=Conversation",
"content": "<p>Let ABC be an isosceles triangle with |AB| = |AC|, and let D be point on side BC. Then<br />|𝐴𝐵|²=|𝐴𝐷|²+|𝐵𝐷|⋅|𝐷𝐶| .</p><p>This reduces to the Pythagorean theorem when |BD| = |DC|. But can you prove the result without assuming the Pythagorean theorem?</p>",
"contentMap": {
"en": "<p>Let ABC be an isosceles triangle with |AB| = |AC|, and let D be point on side BC. Then<br />|𝐴𝐵|²=|𝐴𝐷|²+|𝐵𝐷|⋅|𝐷𝐶| .</p><p>This reduces to the Pythagorean theorem when |BD| = |DC|. But can you prove the result without assuming the Pythagorean theorem?</p>"
},
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109303509329897727/activity",
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"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-11-07T16:39:52Z",
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],
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],
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109303498848521374/activity",
"type": "Announce",
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/109291851035022501/activity",
"type": "Announce",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-11-05T15:15:01Z",
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"https://www.w3.org/ns/activitystreams#Public"
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"cc": [
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108244963695632373/activity",
"type": "Create",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-05-04T17:57:48Z",
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"object": {
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"type": "Note",
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"published": "2022-05-04T17:57:48Z",
"url": "https://mathstodon.xyz/@davidradcliffe/108244963695632373",
"attributedTo": "https://mathstodon.xyz/users/davidradcliffe",
"to": [
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],
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"atomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/108244963695632373",
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"conversation": "tag:mathstodon.xyz,2022-05-04:objectId=24953704:objectType=Conversation",
"content": "<p><span class=\"h-card\" translate=\"no\"><a href=\"https://mathstodon.xyz/@icecolbeveridge\" class=\"u-url mention\">@<span>icecolbeveridge</span></a></span> I can see that</p><p>\\[12^3 + 1^3 \\equiv (-2)^3 + 1^3 \\equiv 0 \\pmod{7},\\] </p><p>but I'm not sure how satisfying that is.</p>",
"contentMap": {
"en": "<p><span class=\"h-card\" translate=\"no\"><a href=\"https://mathstodon.xyz/@icecolbeveridge\" class=\"u-url mention\">@<span>icecolbeveridge</span></a></span> I can see that</p><p>\\[12^3 + 1^3 \\equiv (-2)^3 + 1^3 \\equiv 0 \\pmod{7},\\] </p><p>but I'm not sure how satisfying that is.</p>"
},
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326/activity",
"type": "Create",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-04-28T13:54:08Z",
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"type": "Note",
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"published": "2022-04-28T13:54:08Z",
"url": "https://mathstodon.xyz/@davidradcliffe/108210031742632326",
"attributedTo": "https://mathstodon.xyz/users/davidradcliffe",
"to": [
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],
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"atomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326",
"inReplyToAtomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390",
"conversation": "tag:mathstodon.xyz,2022-04-26:objectId=24732218:objectType=Conversation",
"content": "<p>Proof: </p><p>By the Axiom of Choice, there exists a subset 𝑆 of ℝ that contains exactly one element from each coset of ℤ+√2ℤ .</p><p>For each 𝑥∈ℝ there exist unique elements 𝑠ₓ∈𝑆 and 𝑚ₓ,𝑛ₓ∈ℤ so that 𝑥=𝑠ₓ+𝑚ₓ+𝑛ₓ√2 .</p><p>Define 𝑔(𝑥)=𝑚ₓ and \\(h(x)=\\lfloor s_x+n_x\\sqrt2\\rfloor\\).</p><p>Then 𝑓(𝑥)=𝑔(𝑥)+h(𝑥) , 𝑔(𝑥) has period \\(\\sqrt2\\) , and h(𝑥) has period 1.</p>",
"contentMap": {
"en": "<p>Proof: </p><p>By the Axiom of Choice, there exists a subset 𝑆 of ℝ that contains exactly one element from each coset of ℤ+√2ℤ .</p><p>For each 𝑥∈ℝ there exist unique elements 𝑠ₓ∈𝑆 and 𝑚ₓ,𝑛ₓ∈ℤ so that 𝑥=𝑠ₓ+𝑚ₓ+𝑛ₓ√2 .</p><p>Define 𝑔(𝑥)=𝑚ₓ and \\(h(x)=\\lfloor s_x+n_x\\sqrt2\\rfloor\\).</p><p>Then 𝑓(𝑥)=𝑔(𝑥)+h(𝑥) , 𝑔(𝑥) has period \\(\\sqrt2\\) , and h(𝑥) has period 1.</p>"
},
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{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390/activity",
"type": "Create",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-04-26T17:20:00Z",
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"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390",
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"published": "2022-04-26T17:20:00Z",
"url": "https://mathstodon.xyz/@davidradcliffe/108199516615688390",
"attributedTo": "https://mathstodon.xyz/users/davidradcliffe",
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"atomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390",
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"conversation": "tag:mathstodon.xyz,2022-04-26:objectId=24732218:objectType=Conversation",
"content": "<p>Can you show that<br />\\[f(x) := \\lfloor x\\rfloor\\]<br />is the sum of two periodic functions?</p>",
"contentMap": {
"en": "<p>Can you show that<br />\\[f(x) := \\lfloor x\\rfloor\\]<br />is the sum of two periodic functions?</p>"
},
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"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390/shares",
"type": "Collection",
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},
{
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108197466959898749/activity",
"type": "Create",
"actor": "https://mathstodon.xyz/users/davidradcliffe",
"published": "2022-04-26T08:38:45Z",
"to": [
"https://www.w3.org/ns/activitystreams#Public"
],
"cc": [
"https://mathstodon.xyz/users/davidradcliffe/followers"
],
"object": {
"id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108197466959898749",
"type": "Note",
"summary": null,
"inReplyTo": null,
"published": "2022-04-26T08:38:45Z",
"url": "https://mathstodon.xyz/@davidradcliffe/108197466959898749",
"attributedTo": "https://mathstodon.xyz/users/davidradcliffe",
"to": [
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"conversation": "tag:mathstodon.xyz,2022-04-26:objectId=24717554:objectType=Conversation",
"content": "<p>Testing.</p><p>\\[0^{0^{0^{0^{0^{0^{0^{\\dots}}}}}}} = \\frac12\\]</p>",
"contentMap": {
"en": "<p>Testing.</p><p>\\[0^{0^{0^{0^{0^{0^{0^{\\dots}}}}}}} = \\frac12\\]</p>"
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"published": "2018-08-18T17:55:51Z",
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"content": "<p><span class=\"h-card\" translate=\"no\"><a href=\"https://mathstodon.xyz/@christianp\" class=\"u-url mention\">@<span>christianp</span></a></span> A forward slash is sometimes used for this, e.g. <a href=\"https://en.wikipedia.org/wiki/Wheel_theory\" target=\"_blank\" rel=\"nofollow noopener noreferrer\" translate=\"no\"><span class=\"invisible\">https://</span><span class=\"ellipsis\">en.wikipedia.org/wiki/Wheel_th</span><span class=\"invisible\">eory</span></a></p>",
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"en": "<p><span class=\"h-card\" translate=\"no\"><a href=\"https://mathstodon.xyz/@christianp\" class=\"u-url mention\">@<span>christianp</span></a></span> A forward slash is sometimes used for this, e.g. <a href=\"https://en.wikipedia.org/wiki/Wheel_theory\" target=\"_blank\" rel=\"nofollow noopener noreferrer\" translate=\"no\"><span class=\"invisible\">https://</span><span class=\"ellipsis\">en.wikipedia.org/wiki/Wheel_th</span><span class=\"invisible\">eory</span></a></p>"
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"content": "<p>\\[\\sum_{n=1}^{\\infty} \\frac{n(n+1)/2}{(2n+1)!!^2} = \\frac18\\]</p>",
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"content": "<p>Current mood:</p><p>class Circle:<br /> pass</p><p>circle = Circle()<br />circle.circle = circle</p>",
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"content": "<p>\\[ \\sum_{n=1}^{\\infty} \\sin^2(\\pi n! e) < \\infty \\]</p>",
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"content": "<p><span class=\"h-card\" translate=\"no\"><a href=\"https://mathstodon.xyz/@chase\" class=\"u-url mention\">@<span>chase</span></a></span> Hi Chase! Your equation looks very familiar. Did we meet on Tuesday at a Chinese restaurant?</p>",
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"content": "<p>I wrote a Python script to look for circle packings. I can fit 20 circles of diameter 1 inside a circle of diameter 5.124. This is very close to the best known solution, which has diameter 5.122. Maybe .I can find a new record if I keep searching. <a href=\"https://mathstodon.xyz/media/-owErmTnaxnK2FgTVI4\" target=\"_blank\" rel=\"nofollow noopener noreferrer\" translate=\"no\"><span class=\"invisible\">https://</span><span class=\"ellipsis\">mathstodon.xyz/media/-owErmTna</span><span class=\"invisible\">xnK2FgTVI4</span></a></p>",
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"content": "<p>Proof without words that a pentagonal number is 1/3 of a triangular number. <a href=\"https://mathstodon.xyz/media/_eUukzGyWYYzMNg3rh8\" target=\"_blank\" rel=\"nofollow noopener noreferrer\" translate=\"no\"><span class=\"invisible\">https://</span><span class=\"ellipsis\">mathstodon.xyz/media/_eUukzGyW</span><span class=\"invisible\">YYzMNg3rh8</span></a></p>",
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"content": "<p>O hai.</p>",
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