A small tool to view real-world ActivityPub objects as JSON! Enter a URL
or username from Mastodon or a similar service below, and we'll send a
request with
the right
Accept
header
to the server to view the underlying object.
{
"@context": [
"https://www.w3.org/ns/activitystreams",
{
"ostatus": "http://ostatus.org#",
"atomUri": "ostatus:atomUri",
"inReplyToAtomUri": "ostatus:inReplyToAtomUri",
"conversation": "ostatus:conversation",
"sensitive": "as:sensitive",
"toot": "http://joinmastodon.org/ns#",
"votersCount": "toot:votersCount",
"blurhash": "toot:blurhash",
"focalPoint": {
"@container": "@list",
"@id": "toot:focalPoint"
},
"Hashtag": "as:Hashtag"
}
],
"id": "https://mathstodon.xyz/users/Picanumeros/statuses/113771766607595064/replies",
"type": "Collection",
"first": {
"id": "https://mathstodon.xyz/users/Picanumeros/statuses/113771766607595064/replies?page=true",
"type": "CollectionPage",
"next": "https://mathstodon.xyz/users/Picanumeros/statuses/113771766607595064/replies?only_other_accounts=true&page=true",
"partOf": "https://mathstodon.xyz/users/Picanumeros/statuses/113771766607595064/replies",
"items": [
{
"id": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443",
"type": "Note",
"summary": null,
"inReplyTo": "https://mathstodon.xyz/users/Picanumeros/statuses/113771766607595064",
"published": "2025-01-04T19:37:08Z",
"url": "https://mathstodon.xyz/@Picanumeros/113771769253386443",
"attributedTo": "https://mathstodon.xyz/users/Picanumeros",
"to": [
"https://mathstodon.xyz/users/Picanumeros/followers"
],
"cc": [
"https://www.w3.org/ns/activitystreams#Public"
],
"sensitive": false,
"atomUri": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443",
"inReplyToAtomUri": "https://mathstodon.xyz/users/Picanumeros/statuses/113771766607595064",
"conversation": "tag:mathstodon.xyz,2025-01-04:objectId=131286784:objectType=Conversation",
"content": "<p>Para hallar la probabilidad de que no haya coincidencia, bastaría con substraer la probabilidad del post anterior a 1 (es decir, sacar su complementario). Nos queda la fórmula que vemos a continuación:</p><p><a href=\"https://mathstodon.xyz/tags/PicaRegalos\" class=\"mention hashtag\" rel=\"tag\">#<span>PicaRegalos</span></a></p>",
"contentMap": {
"es": "<p>Para hallar la probabilidad de que no haya coincidencia, bastaría con substraer la probabilidad del post anterior a 1 (es decir, sacar su complementario). Nos queda la fórmula que vemos a continuación:</p><p><a href=\"https://mathstodon.xyz/tags/PicaRegalos\" class=\"mention hashtag\" rel=\"tag\">#<span>PicaRegalos</span></a></p>"
},
"attachment": [
{
"type": "Document",
"mediaType": "image/png",
"url": "https://media.mathstodon.xyz/media_attachments/files/113/771/768/047/194/152/original/d7c514adcf5666b4.png",
"name": "Se muestra la probabilidad de que haya 0 coincidencias, que se calcula haciendo 1 menos la expresión del post anterior. Quedaría como 1 entre 2 factorial menos 1 entre 3 factorial más 1 entre 4 factorial y así hasta 1 entre N factorial alternando sumas y restas.",
"blurhash": "U7Qcn@j[WBxu%MWCWBWB~qt7xuayWBoft7of",
"focalPoint": [
0,
0
],
"width": 2503,
"height": 344
}
],
"tag": [
{
"type": "Hashtag",
"href": "https://mathstodon.xyz/tags/picaregalos",
"name": "#picaregalos"
}
],
"replies": {
"id": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443/replies",
"type": "Collection",
"first": {
"type": "CollectionPage",
"next": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443/replies?min_id=113771772198571637&page=true",
"partOf": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443/replies",
"items": [
"https://mathstodon.xyz/users/Picanumeros/statuses/113771772198571637"
]
}
},
"likes": {
"id": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443/likes",
"type": "Collection",
"totalItems": 0
},
"shares": {
"id": "https://mathstodon.xyz/users/Picanumeros/statuses/113771769253386443/shares",
"type": "Collection",
"totalItems": 0
}
}
]
}
}