A small tool to view real-world ActivityPub objects as JSON! Enter a URL
or username from Mastodon or a similar service below, and we'll send a
request with
the right
Accept
header
to the server to view the underlying object.
{
"@context": [
"https://www.w3.org/ns/activitystreams",
{
"ostatus": "http://ostatus.org#",
"atomUri": "ostatus:atomUri",
"inReplyToAtomUri": "ostatus:inReplyToAtomUri",
"conversation": "ostatus:conversation",
"sensitive": "as:sensitive",
"toot": "http://joinmastodon.org/ns#",
"votersCount": "toot:votersCount",
"Hashtag": "as:Hashtag"
}
],
"id": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735",
"type": "Note",
"summary": null,
"inReplyTo": null,
"published": "2022-11-07T00:54:03Z",
"url": "https://mathstodon.xyz/@PedanticOwl/109299790226484735",
"attributedTo": "https://mathstodon.xyz/users/PedanticOwl",
"to": [
"https://www.w3.org/ns/activitystreams#Public"
],
"cc": [
"https://mathstodon.xyz/users/PedanticOwl/followers"
],
"sensitive": false,
"atomUri": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735",
"inReplyToAtomUri": null,
"conversation": "tag:mathstodon.xyz,2022-11-07:objectId=28500276:objectType=Conversation",
"content": "<p>Claim. A \\(2\\times 5\\times 6\\) box does not fit into a \\(3\\times 3\\times 7\\) box.</p><p><a href=\"https://mathstodon.xyz/tags/ProofInAToot\" class=\"mention hashtag\" rel=\"tag\">#<span>ProofInAToot</span></a>: If the 1st box fits into the 2nd, then any \\(\\epsilon\\)-neighborhood of the first would fit into an \\(\\epsilon\\)-neighborhood of the second. But an \\(\\epsilon\\)-neighborhood of the 1st box has volume \\[4/3\\pi\\epsilon^3+13\\pi\\epsilon^2+104\\epsilon+60\\] and of the 2nd has volume \\[4/3\\pi\\epsilon^3+13\\pi\\epsilon^2+102\\epsilon+63.\\] For \\(\\epsilon>3/2\\), the first volume exceeds the second. \\(\\square\\)</p>",
"contentMap": {
"en": "<p>Claim. A \\(2\\times 5\\times 6\\) box does not fit into a \\(3\\times 3\\times 7\\) box.</p><p><a href=\"https://mathstodon.xyz/tags/ProofInAToot\" class=\"mention hashtag\" rel=\"tag\">#<span>ProofInAToot</span></a>: If the 1st box fits into the 2nd, then any \\(\\epsilon\\)-neighborhood of the first would fit into an \\(\\epsilon\\)-neighborhood of the second. But an \\(\\epsilon\\)-neighborhood of the 1st box has volume \\[4/3\\pi\\epsilon^3+13\\pi\\epsilon^2+104\\epsilon+60\\] and of the 2nd has volume \\[4/3\\pi\\epsilon^3+13\\pi\\epsilon^2+102\\epsilon+63.\\] For \\(\\epsilon>3/2\\), the first volume exceeds the second. \\(\\square\\)</p>"
},
"attachment": [],
"tag": [
{
"type": "Hashtag",
"href": "https://mathstodon.xyz/tags/proofinatoot",
"name": "#proofinatoot"
}
],
"replies": {
"id": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735/replies",
"type": "Collection",
"first": {
"type": "CollectionPage",
"next": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735/replies?min_id=109299793595588099&page=true",
"partOf": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735/replies",
"items": [
"https://mathstodon.xyz/users/PedanticOwl/statuses/109299793595588099"
]
}
},
"likes": {
"id": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735/likes",
"type": "Collection",
"totalItems": 6
},
"shares": {
"id": "https://mathstodon.xyz/users/PedanticOwl/statuses/109299790226484735/shares",
"type": "Collection",
"totalItems": 4
}
}