ActivityPub Viewer

A small tool to view real-world ActivityPub objects as JSON! Enter a URL or username from Mastodon or a similar service below, and we'll send a request with the right Accept header to the server to view the underlying object.

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{ "@context": [ "https://www.w3.org/ns/activitystreams", { "ostatus": "http://ostatus.org#", "atomUri": "ostatus:atomUri", "inReplyToAtomUri": "ostatus:inReplyToAtomUri", "conversation": "ostatus:conversation", "sensitive": "as:sensitive", "toot": "http://joinmastodon.org/ns#", "votersCount": "toot:votersCount" } ], "id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326", "type": "Note", "summary": null, "inReplyTo": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390", "published": "2022-04-28T13:54:08Z", "url": "https://mathstodon.xyz/@davidradcliffe/108210031742632326", "attributedTo": "https://mathstodon.xyz/users/davidradcliffe", "to": [ "https://www.w3.org/ns/activitystreams#Public" ], "cc": [ "https://mathstodon.xyz/users/davidradcliffe/followers" ], "sensitive": false, "atomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326", "inReplyToAtomUri": "https://mathstodon.xyz/users/davidradcliffe/statuses/108199516615688390", "conversation": "tag:mathstodon.xyz,2022-04-26:objectId=24732218:objectType=Conversation", "content": "<p>Proof: </p><p>By the Axiom of Choice, there exists a subset 𝑆 of ℝ that contains exactly one element from each coset of ℤ+√2ℤ .</p><p>For each 𝑥∈ℝ there exist unique elements 𝑠ₓ∈𝑆 and 𝑚ₓ,𝑛ₓ∈ℤ so that 𝑥=𝑠ₓ+𝑚ₓ+𝑛ₓ√2 .</p><p>Define 𝑔(𝑥)=𝑚ₓ and \\(h(x)=\\lfloor s_x+n_x\\sqrt2\\rfloor\\).</p><p>Then 𝑓(𝑥)=𝑔(𝑥)+h(𝑥) , 𝑔(𝑥) has period \\(\\sqrt2\\) , and h(𝑥) has period 1.</p>", "contentMap": { "en": "<p>Proof: </p><p>By the Axiom of Choice, there exists a subset 𝑆 of ℝ that contains exactly one element from each coset of ℤ+√2ℤ .</p><p>For each 𝑥∈ℝ there exist unique elements 𝑠ₓ∈𝑆 and 𝑚ₓ,𝑛ₓ∈ℤ so that 𝑥=𝑠ₓ+𝑚ₓ+𝑛ₓ√2 .</p><p>Define 𝑔(𝑥)=𝑚ₓ and \\(h(x)=\\lfloor s_x+n_x\\sqrt2\\rfloor\\).</p><p>Then 𝑓(𝑥)=𝑔(𝑥)+h(𝑥) , 𝑔(𝑥) has period \\(\\sqrt2\\) , and h(𝑥) has period 1.</p>" }, "attachment": [], "tag": [], "replies": { "id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326/replies", "type": "Collection", "first": { "type": "CollectionPage", "next": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326/replies?only_other_accounts=true&page=true", "partOf": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326/replies", "items": [] } }, "likes": { "id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326/likes", "type": "Collection", "totalItems": 5 }, "shares": { "id": "https://mathstodon.xyz/users/davidradcliffe/statuses/108210031742632326/shares", "type": "Collection", "totalItems": 0 } }